Friday, April 12, 2013

Parallel Resistance (1/Ri=1/R1+1/R2+1/R3+.......+1/Rn)

Parallel Resistance


#include<stdio.h>
#include<conio.h>
#include<math.h>
main()
{
    int i,j,n;
    float a=1.0,b,c=0.0,sum=0.0,temp=0.0;
    printf("\tIt's a programe of 1/Ri=1/R1+1/R2+1/R3+.......+1/Rn\n");
    printf("\n\nEnter the number of registors in parallel: ");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    {
        for(j=1;j<=1;j++)
        printf("\n\tEnter the valuse of %d registor:",i);
        scanf("%f",&b);
        c=a/b;
        sum+=c;
    }
    temp=a/sum;
    printf("\n\nThe total registance(1/Ri) of parallel is: %0.3f\n ",sum);
    printf("\nThe total registance(Ri) of parallel is: %0.3f\n\n ",temp);

}

1 comment:

  1. #include
    main()
    {
    int i,j,n;
    float a=1.0,p=0.0,q=0.0,r,sum=0.0;
    printf("\tIT'S A PROGRAM OF 1/Ri=1/R1+1/R2+1/R3......+1/Rn\n\n");
    printf("How many series you use:");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    {
    for(j=1;j<=1;j++)
    printf("\n\tEnter the regestence:");
    scanf("%f",&r);
    p=(a/r);
    sum+=p;
    }
    q=a/sum;
    printf("\nTotel resestence value(Ri) is:%f\n",q);


    }

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